48x^2+96x-148=0

Solution for 48x^2+96x-148=0 equation:

48x^2+96x-148=0

a = 48; b = 96; c = -148;
Δ = b2-4ac
Δ = 962-4·48·(-148)
Δ = 37632
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{37632}=\sqrt{12544*3}=\sqrt{12544}*\sqrt{3}=112\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-112\sqrt{3}}{2*48}=\frac{-96-112\sqrt{3}}{96}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+112\sqrt{3}}{2*48}=\frac{-96+112\sqrt{3}}{96}
$